Melting and Recasting


 
 
Concept Explanation
 

Melting and Recasting

Conversion From One Shape to Another: When you convert one solid shape to another, its volume remains the same, no matter how different the new shape is.

Example: Twenty seven solid iron spheres, each of radius r and surface area S are melted to form a sphere with surface area S'. Find the:   large (i)  radius r' of the new sphere. large (ii) ratio of S and S'

Solution:  large (i)  We have, Volume of 27 solid spheres, each of radius r =large 27times frac{4}{3}pi r^{3} = 36 pi r^{3}

But volume of 27 solid spheres = Volume of sphere of radius r1 large 36 pi r^{3} = frac{4}{3}pi r_1^{3} Rightarrow r_1^{3} Rightarrow r_1 = 3r

large (ii) We have,  large S_1 = 4pi r_1^{2} = 4pi times (3r)^{2} = 36pi r^{2}

large therefore          large S:S1=4pi r^{2} : 36pi r^{2} = 1:9

Sample Questions
(More Questions for each concept available in Login)
Question : 1

A metalic sphere of radius 4.2 cm is melted and recast into the shape of a cylinder of radius 6cm. Find the height of the cylinder.

Right Option : A
View Explanation
Explanation
Question : 2

A cubical block of gold was melted and cast into 10 smaller cubes of edge 1.5 cm. The volume of the cubical block of gold was ________________

Right Option : B
View Explanation
Explanation
Question : 3

Half cubic metre of gold-sheet is extended by hammering so as to cover an area of 1 hectare. Find the thickness of the gold-sheet.

Right Option : B
View Explanation
Explanation
 
Video Link - Have a look !!!
 
Language - English
 
Chapters
Content / Category
Class / Course
 
 
Related Videos
Language - English

Language - English

Language - English


Language - English
Language - English
Language - English

Language - English
Language - English
Language - English

Language - English


Students / Parents Reviews [10]